3.10.77 \(\int \frac {(a+b x)^2}{(a c-b c x)^5} \, dx\)

Optimal. Leaf size=56 \[ \frac {a^2}{b c^5 (a-b x)^4}-\frac {4 a}{3 b c^5 (a-b x)^3}+\frac {1}{2 b c^5 (a-b x)^2} \]

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Rubi [A]  time = 0.02, antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {43} \begin {gather*} \frac {a^2}{b c^5 (a-b x)^4}-\frac {4 a}{3 b c^5 (a-b x)^3}+\frac {1}{2 b c^5 (a-b x)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^2/(a*c - b*c*x)^5,x]

[Out]

a^2/(b*c^5*(a - b*x)^4) - (4*a)/(3*b*c^5*(a - b*x)^3) + 1/(2*b*c^5*(a - b*x)^2)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {(a+b x)^2}{(a c-b c x)^5} \, dx &=\int \left (\frac {4 a^2}{c^5 (a-b x)^5}-\frac {4 a}{c^5 (a-b x)^4}+\frac {1}{c^5 (a-b x)^3}\right ) \, dx\\ &=\frac {a^2}{b c^5 (a-b x)^4}-\frac {4 a}{3 b c^5 (a-b x)^3}+\frac {1}{2 b c^5 (a-b x)^2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 35, normalized size = 0.62 \begin {gather*} \frac {a^2+2 a b x+3 b^2 x^2}{6 b c^5 (a-b x)^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^2/(a*c - b*c*x)^5,x]

[Out]

(a^2 + 2*a*b*x + 3*b^2*x^2)/(6*b*c^5*(a - b*x)^4)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(a+b x)^2}{(a c-b c x)^5} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(a + b*x)^2/(a*c - b*c*x)^5,x]

[Out]

IntegrateAlgebraic[(a + b*x)^2/(a*c - b*c*x)^5, x]

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fricas [A]  time = 1.16, size = 78, normalized size = 1.39 \begin {gather*} \frac {3 \, b^{2} x^{2} + 2 \, a b x + a^{2}}{6 \, {\left (b^{5} c^{5} x^{4} - 4 \, a b^{4} c^{5} x^{3} + 6 \, a^{2} b^{3} c^{5} x^{2} - 4 \, a^{3} b^{2} c^{5} x + a^{4} b c^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/(-b*c*x+a*c)^5,x, algorithm="fricas")

[Out]

1/6*(3*b^2*x^2 + 2*a*b*x + a^2)/(b^5*c^5*x^4 - 4*a*b^4*c^5*x^3 + 6*a^2*b^3*c^5*x^2 - 4*a^3*b^2*c^5*x + a^4*b*c
^5)

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giac [A]  time = 1.07, size = 64, normalized size = 1.14 \begin {gather*} \frac {\frac {6 \, a^{2}}{{\left (b c x - a c\right )}^{4} b} + \frac {8 \, a}{{\left (b c x - a c\right )}^{3} b c} + \frac {3}{{\left (b c x - a c\right )}^{2} b c^{2}}}{6 \, c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/(-b*c*x+a*c)^5,x, algorithm="giac")

[Out]

1/6*(6*a^2/((b*c*x - a*c)^4*b) + 8*a/((b*c*x - a*c)^3*b*c) + 3/((b*c*x - a*c)^2*b*c^2))/c

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maple [A]  time = 0.00, size = 51, normalized size = 0.91 \begin {gather*} \frac {\frac {a^{2}}{\left (b x -a \right )^{4} b}+\frac {4 a}{3 \left (b x -a \right )^{3} b}+\frac {1}{2 \left (b x -a \right )^{2} b}}{c^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^2/(-b*c*x+a*c)^5,x)

[Out]

1/c^5*(a^2/b/(b*x-a)^4+1/2/(b*x-a)^2/b+4/3/(b*x-a)^3*a/b)

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maxima [A]  time = 1.38, size = 78, normalized size = 1.39 \begin {gather*} \frac {3 \, b^{2} x^{2} + 2 \, a b x + a^{2}}{6 \, {\left (b^{5} c^{5} x^{4} - 4 \, a b^{4} c^{5} x^{3} + 6 \, a^{2} b^{3} c^{5} x^{2} - 4 \, a^{3} b^{2} c^{5} x + a^{4} b c^{5}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/(-b*c*x+a*c)^5,x, algorithm="maxima")

[Out]

1/6*(3*b^2*x^2 + 2*a*b*x + a^2)/(b^5*c^5*x^4 - 4*a*b^4*c^5*x^3 + 6*a^2*b^3*c^5*x^2 - 4*a^3*b^2*c^5*x + a^4*b*c
^5)

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mupad [B]  time = 0.05, size = 76, normalized size = 1.36 \begin {gather*} \frac {\frac {a\,x}{3}+\frac {b\,x^2}{2}+\frac {a^2}{6\,b}}{a^4\,c^5-4\,a^3\,b\,c^5\,x+6\,a^2\,b^2\,c^5\,x^2-4\,a\,b^3\,c^5\,x^3+b^4\,c^5\,x^4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^2/(a*c - b*c*x)^5,x)

[Out]

((a*x)/3 + (b*x^2)/2 + a^2/(6*b))/(a^4*c^5 + b^4*c^5*x^4 - 4*a*b^3*c^5*x^3 + 6*a^2*b^2*c^5*x^2 - 4*a^3*b*c^5*x
)

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sympy [A]  time = 0.44, size = 85, normalized size = 1.52 \begin {gather*} - \frac {- a^{2} - 2 a b x - 3 b^{2} x^{2}}{6 a^{4} b c^{5} - 24 a^{3} b^{2} c^{5} x + 36 a^{2} b^{3} c^{5} x^{2} - 24 a b^{4} c^{5} x^{3} + 6 b^{5} c^{5} x^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**2/(-b*c*x+a*c)**5,x)

[Out]

-(-a**2 - 2*a*b*x - 3*b**2*x**2)/(6*a**4*b*c**5 - 24*a**3*b**2*c**5*x + 36*a**2*b**3*c**5*x**2 - 24*a*b**4*c**
5*x**3 + 6*b**5*c**5*x**4)

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